案件Case白鷺 葵(導航員)Aoi Shirasagi (Navigator)解離巨獸Entropy Crack花守 鈴Suzu Hanamori朝霧 晴Haru Asagiri櫻庭 小春Koharu Sakuraba狐森 紺Kon KitsunemoriCASE 1CASE 1第一關:失衡的原子核The Missing Decimals原子序 Z・原子量・同位素・質量數Atomic number Z · atomic weight · isotopes · mass numberCASE 2CASE 2第二關:機率迷霧與量子跳躍The Electron's AlibiBohr 模型 vs 波動力學・四個量子數・包立不相容原理Bohr vs wave-mechanical model · four quantum numbers · Pauli exclusionCASE 3CASE 3第三關:極性風暴與價電子掠奪Profiling on the Periodic Table價電子・電負度差 Δχ・離子鍵 vs 共價鍵Valence electrons · electronegativity difference Δχ · ionic vs covalentCASE 4 ・ FINALCASE 4 · FINAL終極 BOSS 戰——破裂邊界Forces at WarFN = FA + FR・EN 曲線・r₀ 與 E₀・熔點・熱膨脹F_N = F_A + F_R · E_N curve · r₀ and E₀ · melting point · thermal expansion這裡是 AEML 微觀搜查本部,我是導航員白鷺葵。This is AEML Micro-Investigation HQ. I'm your navigator, Aoi Shirasagi.鋼橋檢驗報告寫著:Fe 的原子量 = 55.85。如果原子核只由「整數個」質子與中子組成,這個 .85 是從哪裡來的?The steel-bridge report says Fe's atomic weight is 55.85. If a nucleus is made of a whole number of protons and neutrons, where does the .85 come from?縮小裝置啟動!真相,就藏在原子裡。Shrink device on! The truth is hiding inside the atom.Case 1:失衡的同位素反應爐。收集 6 顆質子(Z = 6),重建碳原子核!Case 1: the unbalanced isotope reactor. Collect 6 protons (Z = 6) to rebuild a carbon nucleus!Z 決定元素身分——Z 一變,元素就換人。中子數 N 可以改變,形成同位素;質量數 A ≈ Z + N。Z decides the element — change Z and it's a different element. The neutron number N can vary, giving isotopes; mass number A ≈ Z + N.注意:每收集一顆中子,你的質量變大,重力也跟著變大!Careful: every neutron you collect adds mass — and your gravity grows with it!碳原子核重建完成!你組出的是 C-{A}(Z = 6、N = {N})。Carbon nucleus rebuilt! You formed C-{A} (Z = 6, N = {N}).天然碳是 C-12 與 C-13 的固定比例混合。週期表上的原子量是各同位素的「加權平均」,所以帶小數點——.85 的真兇,就是同位素!Natural carbon is a fixed mix of C-12 and C-13. The atomic weight on the periodic table is a weighted average of the isotopes — so it has decimals. The culprit behind .85 is the isotope!Case 2:電子的不在場證明。Bohr 說電子沿固定圓形軌道運行——但那是被推翻的證詞。Case 2: The Electron's Alibi. Bohr said electrons ride fixed circular orbits — testimony that has been overturned.發光的圓形「軌道」一踩就碎!請站在藍色電子雲上——那是 Ψ² 機率最高的區域。The glowing circular "orbits" shatter underfoot! Stand on the blue clouds — where Ψ² is highest.軌域電梯:一個軌域最多兩顆電子,而且自旋必須相反。按「切換」改變你的自旋 ↑/↓!Orbital elevators: one orbital holds at most two electrons, with opposite spins. Press Switch to flip your spin ↑/↓!沿路收集副殼層證物(1s²、2s²……),結案時要用來建立鈣的檔案。小心假證物!Collect subshell evidence (1s², 2s², …) — you'll need it to profile calcium at the end. Beware of fakes!不在場證明成立——電子從來就不在任何一個「點」上,只有 (n, ℓ, mℓ, ms) 四個身分編號。The alibi holds — the electron was never at a single point. All it has is its ID: (n, ℓ, mℓ, ms).Case 3:週期表上的側寫。離子風暴中的元素妖會掠奪你的價電子!Case 3: Profiling on the Periodic Table. Element spirits in the ion storm will steal your valence electrons!你的裝甲核心是鈉 Na(χ = 0.9)。看敵人身上的 χ,算出電負度差 Δχ。Your armor core is sodium Na (χ = 0.9). Read each enemy's χ and compute Δχ.Δχ ≥ 1.7 → 切換為「離子鍵護盾」(電子轉移);Δχ < 1.7 → 切換為「共價鍵鎖定」(共用電子)。按「切換」換模式,按 Space 發射符咒!Δχ ≥ 1.7 → Ionic Shield (electron transfer); Δχ < 1.7 → Covalent Lock (shared electrons). Press Switch to change mode, Space to throw a talisman!核心切換為氯 Cl(χ = 3.0)!同為鹵素的敵人現在和你電負度相近——重新計算 Δχ!Core switched to chlorine Cl (χ = 3.0)! Fellow halogens now have a similar χ to yours — recompute Δχ!動機只有一個:把最外層湊成 8 個電子——不是搶、就是送、不然就共用。Δχ 的大小直接預告鍵結型態。One motive only: complete an outer shell of 8 — take, give, or share. The size of Δχ predicts the bond type.Case 4:引力與斥力的角力。解離巨獸正企圖拉斷鋼骨大樓的晶格鍵結!Case 4: Forces at War. The Entropy Crack is trying to tear apart the steel tower's lattice bonds!看上方儀表:r > r₀ 時淨力為引力——對牠發射「引力符咒」,把鍵長拉回來!Watch the gauge: when r > r₀ the net force is attractive — throw attraction talismans to pull the bond back!r < r₀ 時斥力急遽上升——踩著斥力原子核彈起,從上方反擊牠的頭頂!When r < r₀ repulsion soars — bounce off the repulsion nuclei and strike its head from above!牠疲勞時,站到金色鍵結鎖定栓前,在 r = r₀ 的瞬間按 Space,把鍵結鎖在位能井底 E₀!When it tires, stand at the golden bond-lock bolt and press Space the instant r = r₀ to lock the bond at the bottom of the well, E₀!鍵結鎖定完成!井越深(E₀ 大)→ 熔點越高;井底越陡 → 彈性模數越大;井越不對稱 → 熱膨脹越大。Bond locked! Deeper well (larger E₀) → higher melting point; steeper well bottom → higher elastic modulus; more asymmetric well → larger thermal expansion.哈哈哈!所有的鍵都會被我拉斷——熵永遠是贏家!Ha ha ha! I'll tear every bond apart — entropy always wins!拉不斷?那就把你們全部壓碎!Can't pull you apart? Then I'll crush you together!怎……怎麼可能……力量……竟然平衡了……Im... impossible... the forces... are balanced...最後一步:用你蒐集的副殼層證物,建立鈣 Ca(Z = 20)的完整電子組態——鈣是水泥化學的主角!Final step: use your subshell evidence to build the full electron configuration of calcium Ca (Z = 20) — the star of cement chemistry!完全正確!Ca:1s² 2s² 2p⁶ 3s² 3p⁶ 4s²。價電子 2 個(4s²)——Ca 失去它們成為 Ca²⁺。真相永遠只有一個!Exactly right! Ca: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s². Two valence electrons (4s²) — lose them and Ca becomes Ca²⁺. There is only one truth!推理有破綻!提示:沿對角線規則 1s → 2s → 2p → 3s → 3p → 4s 填入,電子總數必須等於 Z = 20;ℓ 只能是 0 ~ n−1。There's a hole in your deduction! Hint: follow the diagonal rule 1s → 2s → 2p → 3s → 3p → 4s; the total must equal Z = 20, and ℓ can only be 0 to n−1.「原來這棟大樓能耐震,全靠平衡距離 r₀ 與位能井 E₀ 的深淺啊!」"So this tower survives earthquakes all thanks to the equilibrium distance r₀ and the depth of the energy well E₀!"發光的原子核會產生強大斥力。貼近時按跳躍,借斥力高高彈起!Glowing nuclei push back hard. Jump right next to one to ride the repulsion skyward!看到金色鍵結點了嗎?按「鉤爪」發射共價鍵鏈盪過去,再按一次放開!See the gold bonding node? Press Grapple to fire a covalent chain and swing — press again to let go!不穩定的軌道一踩就會崩塌,快速通過!Unstable orbits crumble the moment you land — keep moving!鍵結鎖定柱!站在柱前按 Space 開始校準,指針到 r₀(FN = 0)時再按一次!A bond-lock pillar! Stand by it and press Space to start calibrating, then press again when the needle hits r₀ (FN = 0)!量子衝刺:每次離地可衝刺一次,空中也能使用!Quantum Dash: one dash per jump — it works in mid-air!自由電子海:金屬鍵的價電子不屬於任何原子。在這裡可以高速滑行!Electron sea: metallic valence electrons belong to no single atom. Glide through at high speed!離子磁壁:陰陽離子的庫倫引力會吸住你。貼牆時按跳躍可以蹬牆跳!Ionic walls: the Coulomb attraction between ± ions holds you. Jump while clinging to wall-jump!電梯上已有一顆 ↑ 電子。先切換成 ↓ 自旋再進入!This elevator already holds a ↑ electron. Switch to ↓ spin before boarding!包立不相容!兩顆電子不能擁有完全相同的四個量子數——請切換自旋!Pauli exclusion! Two electrons can't share all four quantum numbers — flip your spin!假證物!{X} 不存在:ℓ 只能是 0 ~ n−1。Fake evidence! {X} doesn't exist: ℓ can only be 0 to n−1.取得證物 {X}Evidence found: {X}Z = {Z} → {E}:Z 一變,元素就換人!Z = {Z} → {E}: change Z, change the element!N = {N}:質量數 A = {A},重力 ×{G}N = {N}: mass number A = {A}, gravity ×{G}鳥居未開啟:需要 Z = 6(目前 Z = {Z})。The torii is sealed: Z = 6 required (now Z = {Z}).鳥居未開啟:碳的穩定原子核需要 N ≥ 6(目前 N = {N})。The torii is sealed: a stable carbon nucleus needs N ≥ 6 (now N = {N}).離子鍵!Δχ = {D} → 電子轉移成功Ionic bond! Δχ = {D} → electron transferred共價鍵!Δχ = {D} → 共用電子鎖定Covalent bond! Δχ = {D} → electrons shared模式錯誤!Δχ = {D},應使用「{M}」Wrong mode! Δχ = {D} — use {M}價電子被掠奪了!Valence electron stolen!檢查點:石燈籠已點亮Checkpoint: stone lantern lit已存檔Saved已讀檔Loaded此欄位沒有存檔This slot is empty存檔碼無效Invalid save code存檔碼已產生並複製Save code created and copied此裝置無法使用 WebGPU,已改用軟體繪圖WebGPU isn't available on this device — switched to software rendering此瀏覽器不支援原生全螢幕,已改用滿版模式Native full screen isn't supported here — using full-window mode完美平衡!PERFECTPERFECT EQUILIBRIUM!接近平衡 GOODGOOD — almost balanced太近了!斥力 FR 把你彈開Too close! Repulsion FR blasts you away太遠了!引力 FA 不足Too far! Attraction FA is too weak鍵結鎖定!通道已建立Bond locked! A path has formed受到攻擊!Ouch!鍵被拉斷了!鋼骨晶格受損The bond snapped! The steel lattice is damaged斥力反擊!Repulsive counter!引力命中!r 縮短Attraction hit! r shortens巨獸疲勞了!前往鍵結鎖定栓!The beast is exhausted! Go to the bond-lock bolt!C-12:最常見的穩定同位素(約 98.9%)C-12: the most common stable isotope (~98.9%)C-13:穩定同位素(約 1.1%)C-13: a stable isotope (~1.1%)C-14:放射性同位素,碳十四定年就是靠它!C-14: radioactive — the basis of radiocarbon dating!中子過多,原子核不穩定!Too many neutrons — the nucleus is unstable!核心切換:Cl(χ = 3.0)Core switched: Cl (χ = 3.0)全螢幕Full screen修改過的副本——無法產生有效認證碼Modified copy — no valid token can be produced請輸入姓名與學號Please enter your name and student ID質子 ZProtons Z中子 NNeutrons N質量數 AMass no. A重力Gravity自旋 msSpin ms證物Evidence核心Core模式Mode離子鍵護盾Ionic Shield共價鍵鎖定Covalent Lock鍵長 r/r₀Bond length r / r₀(無)(none)氫 HHydrogen H氦 HeHelium He鋰 LiLithium Li鈹 BeBeryllium Be硼 BBoron B碳 CCarbon C開啟ON關閉OFF目前:WebGPU 硬體繪圖(含光暈後製)Now: WebGPU hardware rendering (with bloom post-FX)目前:軟體繪圖(Canvas 2D)Now: software rendering (Canvas 2D)此裝置不支援 WebGPU,使用軟體繪圖WebGPU not supported on this device — using software請按鍵……Press a key...存檔Save讀檔Load檔案Slot(空白)(empty)推理正確!Correct deduction!推理有誤……Not quite...✔ 認證碼有效✔ Valid token✘ 認證碼無效或與學號不符✘ Invalid token or wrong student ID第 02 號結案檔案卡CASE FILE No. 02 — CLOSED真相的平衡點:微觀破案特攻The Equilibrium Point: Micro-Investigation ACT偵探Detective學號Student ID特偵員Investigator總分Score答題正確率Quiz accuracy平衡打擊Equilibrium strikes平均時機誤差Avg. timing error破案時間Clear time評等Rank破案認證碼Verification token鈣的電子組態Ca configuration工程材料 Ch.02 原子結構與原子間鍵結Engineering Materials Ch.02 Atomic Structure & Interatomic Bonding真相之眼Eye of Truth名偵探Master Detective見習偵探Junior Detective搜查新人Rookie Investigator氯有兩種同位素:³⁵Cl(34.969 amu,75.77%)與 ³⁷Cl(36.966 amu,24.23%)。Cl 的平均原子量約為?Chlorine has two isotopes: ³⁵Cl (34.969 amu, 75.77%) and ³⁷Cl (36.966 amu, 24.23%). Its average atomic weight is about?35.00 amu35.00 amu35.45 amu35.45 amu35.97 amu35.97 amu36.00 amu36.00 amuĀ = Σ fiAi = 0.7577(34.969) + 0.2423(36.966) = 35.45 amu。原子量是加權平均,不是簡單平均。Ā = Σ fiAi = 0.7577(34.969) + 0.2423(36.966) = 35.45 amu — a weighted, not simple, average.
為什麼週期表上 Fe 的原子量是 55.85,而不是整數?Why is iron's atomic weight 55.85 instead of a whole number?實驗室秤量誤差造成Laboratory weighing error電子的質量加上去造成The electrons' mass adds the decimals量到的是各同位素依存在比例的加權平均It is a weighted average over the naturally occurring isotopes中子會隨時間衰變Neutrons decay over time我們量到的從來不是「一顆」原子,而是一整群不同同位素的混合,原子量 Ā = Σ fiAi。We never weigh "one" atom — we weigh a mixture of isotopes, so Ā = Σ fiAi.
鈰 Ce 的同位素:¹⁴⁰Ce 佔 88.45%、¹⁴²Ce 佔 11.11%,其餘極少。不用計算機,Ce 的原子量最接近?Cerium: ¹⁴⁰Ce is 88.45% and ¹⁴²Ce is 11.11%, the rest tiny. Without a calculator, Ce's atomic weight is closest to?137.9137.9139.0139.0140.1140.1141.9141.9答案一定緊貼比例最大的 ¹⁴⁰Ce(139.905),再被 ¹⁴²Ce 往上拉一點 → 約 140.12 amu。It must hug the dominant ¹⁴⁰Ce (139.905), pulled up slightly by ¹⁴²Ce → about 140.12 amu.
下列哪一組量子數 (n, ℓ, mℓ, ms) 不可能存在?Which set of quantum numbers (n, ℓ, mℓ, ms) is impossible?(2, 1, 0, +½)(2, 1, 0, +½)(3, 2, −1, +½)(3, 2, −1, +½)(2, 2, 1, −½)(2, 2, 1, −½)(1, 0, 0, −½)(1, 0, 0, −½)ℓ 只能是 0 ~ n−1。n = 2 時 ℓ 最大為 1,所以 ℓ = 2(2d)不存在。ℓ ranges from 0 to n−1. For n = 2, ℓ ≤ 1, so ℓ = 2 (a "2d") cannot exist.
(3, 2, −1, +½) 描述的電子位於哪一個副殼層?The electron (3, 2, −1, +½) is in which subshell?3s3s3p3p3d3d4d4dn = 3 → 第 3 殼層(M);ℓ = 2 → d。mℓ = −1 是 5 個 d 軌域之一,ms = +½ 為自旋向上。n = 3 → shell M; ℓ = 2 → d. mℓ = −1 is one of five d orbitals; ms = +½ is spin-up.
第 n = 3 殼層最多可以容納幾個電子?How many electrons can the n = 3 shell hold at most?8899181832322n² = 2 × 3² = 18:3s (2) + 3p (6) + 3d (10) = 18。根源是包立不相容原理:每個軌域最多 2 個自旋相反的電子。2n² = 2 × 3² = 18: 3s (2) + 3p (6) + 3d (10). The root cause is Pauli exclusion: two opposite-spin electrons per orbital.
MgO:χMg = 1.2、χO = 3.5。依 %離子性 = {1 − exp[−(Δχ)²/4]} × 100%,約為?MgO: χMg = 1.2, χO = 3.5. Using %IC = {1 − exp[−(Δχ)²/4]} × 100%, the ionic character is about?12%12%51%51%73%73%95%95%Δχ = 2.3;(2.3)²/4 = 1.32;exp(−1.32) = 0.267 → (1 − 0.267) × 100% ≈ 73%。Δχ = 2.3; (2.3)²/4 = 1.32; exp(−1.32) = 0.267 → (1 − 0.267) × 100% ≈ 73%.
Na(…3s¹)與 Cl(…3s² 3p⁵)相遇時,最可能發生什麼事?When Na (…3s¹) meets Cl (…3s² 3p⁵), what most likely happens?兩者各拿出一個電子共用,形成共價鍵Each shares one electron — a covalent bondNa 把 3s 電子交給 Cl,形成 Na⁺ 與 Cl⁻ 的離子鍵Na gives its 3s electron to Cl, forming an ionic bond between Na⁺ and Cl⁻Cl 把電子交給 NaCl gives an electron to Na形成電子海的金屬鍵They form a metallic electron seaΔχ = 3.0 − 0.9 = 2.1(離子性約 67%)。Na 送出 1 個、Cl 收下 1 個,雙方都達到惰性氣體組態。Δχ = 3.0 − 0.9 = 2.1 (~67% ionic). Na gives one, Cl takes one — both reach a noble-gas configuration.
為什麼混凝土、陶瓷等離子性材料又硬又脆?Why are ionic materials such as ceramics and concrete hard but brittle?因為含有很多自由電子They contain many free electrons因為鍵結具有方向性且很弱Their bonds are directional and weak原子面滑移後同性離子相鄰,庫倫斥力使晶體直接斷裂After slip, like-charged ions become neighbours and Coulomb repulsion splits the crystal因為密度太低Their density is too low離子晶體只要滑移半個晶格,原本相鄰的異性離子就變成同性相鄰——滑移 = 斷裂,所以幾乎沒有塑性變形。這正是混凝土需要鋼筋的原因。Slip by half a lattice spacing puts like charges side by side — slip means fracture, so there's almost no plastic deformation. That's why concrete needs rebar.
兩原子位於平衡間距 r₀ 時,下列何者正確?At the equilibrium spacing r₀, which statement is correct?FA 與 FR 都等於零FA and FR are both zeroFN = FA + FR = 0,且位能 EN 最低(= E₀)FN = FA + FR = 0 and the energy EN is minimum (= E₀)位能 EN = 0The energy EN = 0斥力 FR 達到最大Repulsion FR is at its maximumF = dE/dr:淨力為零之處正是 E–r 曲線的最低點。FA 與 FR 並不為零,而是大小相等、方向相反。F = dE/dr: zero net force is exactly the minimum of the E–r curve. FA and FR are not zero — they are equal and opposite.
鍵結能 E₀ 越大(位能井越深)的材料,通常會怎樣?A material with a larger bonding energy E₀ (deeper well) usually has…?熔點越低a lower melting point熔點越高a higher melting point熱膨脹係數越大a larger thermal expansion coefficient彈性模數越小a smaller elastic modulus井越深,要把原子搖散所需的熱能越多 → 熔點 Tm 越高。The deeper the well, the more thermal energy is needed to shake atoms apart → higher Tm.
鑽石(強共價鍵)與鉛(弱金屬鍵)相比,下列何者正確?Comparing diamond (strong covalent) with lead (weak metallic), which is correct?鑽石:井淺而平 → Tm 低、α 大Diamond: shallow, flat well → low Tm, large α鉛:井深而陡 → E 極大Lead: deep, steep well → huge E兩者的 E–r 曲線完全相同Both have identical E–r curves鑽石:井深而陡 → Tm 高、E 極大、α 極小Diamond: deep, steep well → high Tm, huge E, tiny α同一口井解釋三個性質:井深 → 熔點、井底曲率 → 彈性模數、井的不對稱 → 熱膨脹。One well explains three properties: depth → melting point, curvature → elastic modulus, asymmetry → thermal expansion.